Engineering Entrance Exams

A student performs a titration with different burettes and finds titre values of 25.2 mL, 25.25 mL and 25.0 mL. The number of significant figures in the average titre value

nikhil

12 Years agoGrade

3 Answers

Saurabh Koranglekar

6 Years ago

To determine the number of significant figures in the average titre value, follow these steps:

List the given titre values
The student recorded three titre values:

25.2 mL
25.25 mL
25.0 mL
Find the average titre value
The average is calculated as:

Average titre = (25.2 + 25.25 + 25.0) / 3
= 75.45 / 3
= 25.15 mL

Determine the number of significant figures

The titre values have different significant figures:
25.2 mL has 3 significant figures
25.25 mL has 4 significant figures
25.0 mL has 3 significant figures
When averaging, the result should have the same number of decimal places as the value with the fewest decimal places.
The least precise measurement is 25.2 mL (1 decimal place).
Rounding 25.15 mL to 1 decimal place gives 25.2 mL.
Final Answer
The average titre value is 25.2 mL, which has 3 significant figures.

Arun

6 Years ago

We have 25.20,25.25 and 25.00 ml.

Average=

25.20+25.25+25.00

75.45

= 25.15=25.1

In case of division, the final answer will contain as many significant figures as there are in an number with least significant numbers.

So, the significant number is 3.

Krrish

5 Years ago

we have 25.20, 25,25 and 25.0 mlavg.= (25.20+25.25+25.0)/3=75.5/3 (75.5 because when we add significant figures the result cannot have more digits to the right of the decimal point than either of the original numbers which in this case is 25.0. therefore we will have to round off 75.45 to 1 decimal place which is 75.5)=25.16666...=25.2(since when we divide significant figures, our answer cannot have more significant figures than either of the original numbers, ignoring exact numbers like 1,2,3..(basically natural numbers)).number of significant figures in 25.2 = 3Therefore our answer is 3