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A stationary bomb explodes into two parts of masses 3 kg and 1 kg. The total K.E. of the two parts after explosion is 2400J. The K.E. of the smaller part is A 600 J B 1800 J C 1200 J D 2160 J

A stationary bomb explodes into two parts of masses 3 kg and 1 kg. The total K.E. of the two parts after explosion is 2400J. The K.E. of the smaller part is A 600 J B 1800 J C 1200 J D 2160 J

Grade:upto college level

2 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
3 years ago
576-1846_5.PNG
Arun
25750 Points
3 years ago
The initial momentum is zero.
 
let m1=3 kg m2=1 kg & their velocities be v1 & v2 respectively.
 
according to conservationh of momentum 
 
m1v1 + m2v2 = 0
 
3v1 + v2 = 0
 
v2 = -3v1
 
also,
 
 
 
0.5m1v22 + 0.5m2v22 = 24000
 
m1v12 + m2v22 = 4800
 
3v12 + v22 = 4800
 
3v12 +(-3v1)2 = 4800
 
12v12 = 4800
 
v1 = 20
 
v2 = -60 (opp. direction)
 
KE of m2 is 1800.
 
 

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