A spring of spring constant 5*10 3 N/m is stretched initially by 5 cm from the unstretched position. Then the work required to stretch is further by another 5 cm is ?

Question

Saurabh Koranglekar · Answer

Arun · Answer

Here, W=1/2k(x22-x12) = 1/2×5×103((10/100)2-(5/100)2) =1/2×5×103/104(100-25) =18.75J Hence the work required to stretch the spring further by another 5cm is 18.75 N-m

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A spring of spring constant 5*10 3 N/m is stretched initially by 5 cm from the unstretched position. Then the work required to stretch is further by another 5 cm is ?

A spring of spring constant 5*10 3 N/m is stretched initially by 5 cm from the unstretched position. Then the work required to stretch is further by another 5 cm is ?

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A spring of spring constant 5*10 3 N/m is stretched initially by 5 cm from the unstretched position. Then the work required to stretch is further by another 5 cm is ?

A spring of spring constant 5*10 3 N/m is stretched initially by 5 cm from the unstretched position. Then the work required to stretch is further by another 5 cm is ?

2 Answers

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