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A spring of force constant k is cut into two equal halves. The force constant of each half is (A) 3k(B) k (C)k/2(D) 2k

A spring of force constant k is cut into two equal halves. The force constant of each half is
(A) 3k(B) k (C)k/2(D) 2k

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2 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
3 years ago
Dear student

The answer is option d

Regards
Vikas TU
14149 Points
3 years ago
For a spring system kl= constant
k'/k = l/(l/2) 
k' = 2k 
Hence, force constant of each half spring is 2k.

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