A sample of potassium chromate, KCrO4, contains 40.3% K and 26.8% Cr. The mass percent of O in the sample would be:

A. 4 x 16 = 64
B. 40.3 + 26.8 = 67.1
C. 100 - (40.3 + 26.8) = 23.9
D. The mass of the sample is needed to finish the calculation.

Question

Saurabh Koranglekar · Answer

Dear student 100 - (40.3 + 26.8) = 23.9 option c Regadrs

Vikas TU · Answer

Chromium Cr 35.349% Oxygen O 38.070% Potassium K 26.581%............................................................

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A sample of potassium chromate, KCrO4, contains 40.3% K and 26.8% Cr. The mass percent of O in the sample would be: A. 4 x 16 = 64 B. 40.3 + 26.8 = 67.1 C. 100 - (40.3 + 26.8) = 23.9 D. The mass of the sample is needed to finish the calculation.

A sample of potassium chromate, KCrO4, contains 40.3% K and 26.8% Cr. The mass percent of O in the sample would be:

A. 4 x 16 = 64
B. 40.3 + 26.8 = 67.1
C. 100 - (40.3 + 26.8) = 23.9
D. The mass of the sample is needed to finish the calculation.

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A sample of potassium chromate, KCrO4, contains 40.3% K and 26.8% Cr. The mass percent of O in the sample would be: A. 4 x 16 = 64 B. 40.3 + 26.8 = 67.1 C. 100 - (40.3 + 26.8) = 23.9 D. The mass of the sample is needed to finish the calculation.

A sample of potassium chromate, KCrO4, contains 40.3% K and 26.8% Cr. The mass percent of O in the sample would be: A. 4 x 16 = 64 B. 40.3 + 26.8 = 67.1 C. 100 - (40.3 + 26.8) = 23.9 D. The mass of the sample is needed to finish the calculation.

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A sample of potassium chromate, KCrO4, contains 40.3% K and 26.8% Cr. The mass percent of O in the sample would be:

A. 4 x 16 = 64
B. 40.3 + 26.8 = 67.1
C. 100 - (40.3 + 26.8) = 23.9
D. The mass of the sample is needed to finish the calculation.