A rod with rectangular cross section oscillates about a horizontal axis passig through one of its ends and it behave like a second pendulum. Determine it`s length

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Vikas TU · Answer

Dear student T = 2*pie sqrt(I/mgd) - It is Rigid body By parallel axis theorem I = ML^2/12 + M(L/2)^2 = Ml^2/3 d = l/2 T = 2*pie sqrt(2ML^2/3MgL) = 3/2 *1 = 1.5m

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A rod with rectangular cross section oscillates about a horizontal axis passig through one of its ends and it behave like a second pendulum. Determine it`s length

A rod with rectangular cross section oscillates about a horizontal axis passig through one of its ends and it behave like a second pendulum. Determine it`s length

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A rod with rectangular cross section oscillates about a horizontal axis passig through one of its ends and it behave like a second pendulum. Determine it`s length

A rod with rectangular cross section oscillates about a horizontal axis passig through one of its ends and it behave like a second pendulum. Determine it`s length

1 Answers

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Other Related Questions on Engineering Entrance Exams

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