A particle is moving in a straight line. At time t, the distance between the particle from its starting point is given by
x = t – 6t2 + t3. Its acceleration will be zero at
(A) t = 1 unit time (B) t = 2 unit time (C) t = 3 unit time (D) t = 4 unit time

Question

Saurabh Koranglekar · Answer

Dear student Double differentiate and equate to 0 the answer will come to be 2 Regards

Vikas TU · Answer

Using calculus, it's possible to calculate an object's velocity at any moment along its path. This is called instantaneous velocity and it is defined by the equation v = (ds)/(dt), or, in other words, the derivative of the object's average velocity equation.

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A particle is moving in a straight line. At time t, the distance between the particle from its starting point is given by x = t – 6t2 + t3. Its acceleration will be zero at (A) t = 1 unit time (B) t = 2 unit time (C) t = 3 unit time (D) t = 4 unit time

A particle is moving in a straight line. At time t, the distance between the particle from its starting point is given by
x = t – 6t2 + t3. Its acceleration will be zero at
(A) t = 1 unit time (B) t = 2 unit time (C) t = 3 unit time (D) t = 4 unit time

2 Answers

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A particle is moving in a straight line. At time t, the distance between the particle from its starting point is given by x = t – 6t2 + t3. Its acceleration will be zero at (A) t = 1 unit time (B) t = 2 unit time (C) t = 3 unit time (D) t = 4 unit time

A particle is moving in a straight line. At time t, the distance between the particle from its starting point is given by x = t – 6t2 + t3. Its acceleration will be zero at (A) t = 1 unit time (B) t = 2 unit time (C) t = 3 unit time (D) t = 4 unit time

2 Answers

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A particle is moving in a straight line. At time t, the distance between the particle from its starting point is given by
x = t – 6t2 + t3. Its acceleration will be zero at
(A) t = 1 unit time (B) t = 2 unit time (C) t = 3 unit time (D) t = 4 unit time