A particle executing a vibratory motion while passing through the mean position has
(a) Maximum P.E. and minimum K.E.
(b) Maximum K.E. and minimum P.E.
(c) P.E. and K.E. both maximum
(d) P.E. and K.E. both minimum

Question

Arun · Answer

A particle executing a vibratory motion while passing through the mean position has (a) Maximum P.E. and minimum K.E. Hope it helps

Vikas TU · Answer

If an oscillator executing in SHM passes through a fixed point (mean position) then the potential energy of the oscillator is zero but the kinetic energy is maximum.

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A particle executing a vibratory motion while passing through the mean position has (a) Maximum P.E. and minimum K.E. (b) Maximum K.E. and minimum P.E. (c) P.E. and K.E. both maximum (d) P.E. and K.E. both minimum

A particle executing a vibratory motion while passing through the mean position has
(a) Maximum P.E. and minimum K.E.
(b) Maximum K.E. and minimum P.E.
(c) P.E. and K.E. both maximum
(d) P.E. and K.E. both minimum

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A particle executing a vibratory motion while passing through the mean position has (a) Maximum P.E. and minimum K.E. (b) Maximum K.E. and minimum P.E. (c) P.E. and K.E. both maximum (d) P.E. and K.E. both minimum

A particle executing a vibratory motion while passing through the mean position has (a) Maximum P.E. and minimum K.E. (b) Maximum K.E. and minimum P.E. (c) P.E. and K.E. both maximum (d) P.E. and K.E. both minimum

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A particle executing a vibratory motion while passing through the mean position has
(a) Maximum P.E. and minimum K.E.
(b) Maximum K.E. and minimum P.E.
(c) P.E. and K.E. both maximum
(d) P.E. and K.E. both minimum