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A mixture of light, consisting of wavelength 590 nm and an unknown wavelength, illuminates Young’s double slit and gives rise to two overlapping interference patterns on the screen. The central maximum of both lights coincide. Further, it is observed that the third bright fringe of known light coincides with the 4th bright fringe of the unknown light. From this data, the wavelength of the unknown light is ?

A mixture of light, consisting of wavelength 590 nm and an unknown wavelength, illuminates Young’s double slit and gives rise to two overlapping interference patterns on the screen. The central maximum of both lights coincide. Further, it is observed that the third bright fringe of known light coincides with the 4th bright fringe of the unknown light. From this data, the wavelength of the unknown light is ?

Grade:11

2 Answers

Arun
25763 Points
11 months ago
 
Dear Jayant
 
Question is incomplete. Please check and repost the question. You can also attach an image. I will be happy to help you.
Vikas TU
14149 Points
11 months ago
This question related to the concepts of Young's Double Slit Experiment
 
Here, we will use only one concept:
Path Difference for nth bright fringe = n*Lambda

Here, let us name:
Known wavelength = Lambda1  = 590 nm
Unknown wavelength = Lambda2

We are given that the Central Maxima of both lights coincide. This means that there is no initial path difference between the two lights.
Now, third bright fringe of known wavelength light coincides with the fourth bright fringe of the unknown wavelength light.
So, we can write:
3Lambda1 = 4Lambda2 
3*590 = 4Lambda2 
Lambda2 = 442.5nm
 

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