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A metal wire of linear mass density of 9.8 gm is stretched with a tension of 10 kg-wt between two rigid supports 1 metre apart. The wire passes at its middle point between the poles of a per magnet and it vibrates in resonance when carrying an alternating current of frequency n. The frequency n of the alternating source is ?

sudhanshu , 12 Years ago
Grade 12
anser 2 Answers
Saurabh Koranglekar
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Last Activity: 5 Years ago
Arun
The relation between a fundamental frequency and the tension of a wire
is given as
We can also write,
Here f is the fundamental  frequency of the wire, L is the string length and T is the tension in the length and M is the linear mass density.
Given M = 9.8 g/m and L = 1 m and mass, m= 10 kg
Substitute the given values, we get
f = 50 Hz
Thus, The fundamental  frequency of the wire is​ 50 Hz
 
Last Activity: 5 Years ago
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