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A mass M, attached to a horizontal spring executing S.H.M with amplitude A1. When themass M passes through its mean position then a smaller mass m is placed over it andboth of them move together with amplitude A2. The ratio of 12AA???????? is?

A mass M, attached to a horizontal spring executing S.H.M with amplitude A1. When themass M passes through its mean position then a smaller mass m is placed over it andboth of them move together with amplitude A2. The ratio of 12AA???????? is?

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2 Answers

Saurabh Koranglekar
askIITians Faculty 10341 Points
one year ago
Dear student
The ratio of 12AA ???
Please attach the image of the question

Regards
Vikas TU
14149 Points
one year ago
Total energy of string being stretched = E = 1/2kx²
energy of string with amplitude = E = 1/2k (A1)²
E is also the kinetic energy 
M is the mean position
As E is the independent mass so, energy remains the same
so it will be
A1 = A2
or 1: 1
 

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