A mass M, attached to a horizontal spring executing S.H.M with amplitude A1. When themass M passes through its mean position then a smaller mass m is placed over it andboth of them move together with amplitude A2. The ratio of 12AA???????? is?

Question

Saurabh Koranglekar · Answer

Dear student The ratio of 12AA ??? Please attach the image of the question Regards

Vikas TU · Answer

Total energy of string being stretched = E = 1/2kx²
energy of string with amplitude = E = 1/2k (A1)²
E is also the kinetic energy
M is the mean position
As E is the independent mass so, energy remains the same
so it will be
A1 = A2
or 1: 1

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A mass M, attached to a horizontal spring executing S.H.M with amplitude A1. When themass M passes through its mean position then a smaller mass m is placed over it andboth of them move together with amplitude A2. The ratio of 12AA???????? is?

A mass M, attached to a horizontal spring executing S.H.M with amplitude A1. When themass M passes through its mean position then a smaller mass m is placed over it andboth of them move together with amplitude A2. The ratio of 12AA???????? is?

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A mass M, attached to a horizontal spring executing S.H.M with amplitude A1. When themass M passes through its mean position then a smaller mass m is placed over it andboth of them move together with amplitude A2. The ratio of 12AA???????? is?

A mass M, attached to a horizontal spring executing S.H.M with amplitude A1. When themass M passes through its mean position then a smaller mass m is placed over it andboth of them move together with amplitude A2. The ratio of 12AA???????? is?

2 Answers

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