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A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 s. then the coefficient of friction is ?

sudhanshu , 12 Years ago
Grade 12
anser 1 Answers
Asaad
u = 6 m/s v = 0t = 10 sμ = ? v = u + at 0 = 6 + 10aa = - 3/5 m/s2Frictional force=ma=μmgma=μmga=μg
Last Activity: 8 Years ago
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