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A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 s. then the coefficient of friction is ?

A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 s. then the coefficient of friction is ?

Grade:12

1 Answers

Asaad
19 Points
3 years ago
u = 6 m/s v = 0t = 10 sμ = ? v = u + at 0 = 6 + 10aa = - 3/5 m/s2Frictional force=ma=μmgma=μmga=μg

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