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It is given that he throws the next ball after the previous one reaches to top.
It is also given that he is throwing 2 balls each second.
Which means after 0.5 second, the ball reaches its maximum height.
Now,
h=?
u=v+gt (v=u-gt)
u=0+10*0.5
u=5 m/s
v=0 m/s
Putting these in the equation v^2 - u^2=-2gh
0–5^2 = -2×10×h
h=1.25 m.
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