A line passing through the point of intersection of x + y = 4 and x – y = 2 makes an angle tan–1(3/4) with the x-axis. It intersects the parabola y2 = 4(x–3) at points (x1 , y1 ) and (x2 , y2 ) respectively. Then |x1 –x2 | is equal to

(A)16/9

(B)32/9

(C)40/9

(D)80/9

Question

Saurabh Koranglekar · Answer

Vikas TU · Answer

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A line passing through the point of intersection of x + y = 4 and x – y = 2 makes an angle tan–1(3/4) with the x-axis. It intersects the parabola y2 = 4(x–3) at points (x1 , y1 ) and (x2 , y2 ) respectively. Then |x1 –x2 | is equal to (A)16/9 (B)32/9 (C)40/9 (D)80/9

A line passing through the point of intersection of x + y = 4 and x – y = 2 makes an angle tan–1(3/4) with the x-axis. It intersects the parabola y2 = 4(x–3) at points (x1 , y1 ) and (x2 , y2 ) respectively. Then |x1 –x2 | is equal to

(A)16/9

(B)32/9

(C)40/9

(D)80/9

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A line passing through the point of intersection of x + y = 4 and x – y = 2 makes an angle tan–1(3/4) with the x-axis. It intersects the parabola y2 = 4(x–3) at points (x1 , y1 ) and (x2 , y2 ) respectively. Then |x1 –x2 | is equal to (A)16/9 (B)32/9 (C)40/9 (D)80/9

A line passing through the point of intersection of x + y = 4 and x – y = 2 makes an angle tan–1(3/4) with the x-axis. It intersects the parabola y2 = 4(x–3) at points (x1 , y1 ) and (x2 , y2 ) respectively. Then |x1 –x2 | is equal to (A)16/9 (B)32/9 (C)40/9 (D)80/9

2 Answers

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A line passing through the point of intersection of x + y = 4 and x – y = 2 makes an angle tan–1(3/4) with the x-axis. It intersects the parabola y2 = 4(x–3) at points (x1 , y1 ) and (x2 , y2 ) respectively. Then |x1 –x2 | is equal to

(A)16/9

(B)32/9

(C)40/9

(D)80/9