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A cyclist turns around a curve at 15 miles per hour. If he turns at double the speed, the tendency of overturn is (a) doubled (b) quadrupled (c) halved (d) unchanged

A cyclist turns around a curve at 15 miles per hour. If he turns at double the speed, the tendency of overturn is
(a) doubled
(b) quadrupled
(c) halved
(d) unchanged

Grade:Upto college level

2 Answers

Radhey joshi
14 Points
3 years ago
Speed=15miles/hr       . Eqs-1.... ..Initially
   In vertical circular motion 
Tendency to overturn depends on centipital force
         Mv^2/r.      eqs-2
Here velocity is doubled means now is 30miles/hr
We get the value four times
Correct ans-(b)
Dividing  eqs 2 and 1
 
Radhey joshi
14 Points
3 years ago
F directly proportional to v^2
From F=MV^2/r
And F is tendency to overturn in a circular motion
Therefore on doubling velocity
Tendency to overturn becomes quadrupled
And(b)

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