A cyclist turns around a curve at 15 miles per hour. If he turns at double the speed, the tendency of overturn is
(a) doubled
(b) quadrupled
(c) halved
(d) unchanged
sumit kumar , 11 Years ago
Grade Upto college level
2 Answers
Radhey joshi
Last Activity: 6 Years ago
Speed=15miles/hr . Eqs-1.... ..Initially
In vertical circular motion
Tendency to overturn depends on centipital force
Mv^2/r. eqs-2
Here velocity is doubled means now is 30miles/hr
We get the value four times
Correct ans-(b)
Dividing eqs 2 and 1
Radhey joshi
Last Activity: 6 Years ago
F directly proportional to v^2
From F=MV^2/r
And F is tendency to overturn in a circular motion
Therefore on doubling velocity
Tendency to overturn becomes quadrupled
And(b)
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