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A circular loop of radius 0.3 cm lies parallel to a much bigger circular loop of radius 20 cm. The centre of the small loop is on the axis of the bigger loop. The distance between their centres is 15 cm. If a current of 2.0 A flows through the smaller loop, then the flux linked with bigger loop is ?

Jayant Kumar , 12 Years ago
Grade 11
anser 1 Answers
Saurabh Koranglekar

To determine the magnetic flux linked with the larger loop due to the current flowing through the smaller loop, we can use the principles of magnetism, specifically the Biot-Savart Law and the concept of magnetic flux. Let's break this down step by step.

Understanding Magnetic Field from a Current Loop

When current flows through a circular loop, it generates a magnetic field around it. The magnetic field (B) at a point along the axis of a circular loop can be calculated using the formula:

B = (μ₀/4π) * (2πR² * I) / (R² + z²)^(3/2)

Here:

  • μ₀ is the permeability of free space, approximately 4π x 10-7 T·m/A.
  • R is the radius of the smaller loop (0.003 m).
  • I is the current flowing through the smaller loop (2.0 A).
  • z is the distance from the center of the smaller loop to the point where we want to calculate the magnetic field (15 cm = 0.15 m).

Calculating the Magnetic Field at the Larger Loop

Substituting the values into the formula:

B = (μ₀/4π) * (2π(0.003)² * 2.0) / ((0.003)² + (0.15)²)^(3/2)

First, calculate the denominator:

(0.003)² + (0.15)² = 0.000009 + 0.0225 = 0.022509

Now raise this to the power of 3/2:

(0.022509)^(3/2) = 0.0001068 (approximately)

Now plug in the values:

B = (4π x 10-7) / (4π) * (0.000018 * 2.0) / 0.0001068

This simplifies to:

B ≈ (10-7) * (0.000036) / 0.0001068

Calculating this gives:

B ≈ 3.37 x 10-5 T

Calculating the Magnetic Flux through the Larger Loop

The magnetic flux (Φ) linked with a loop is given by the formula:

Φ = B * A

Where A is the area of the larger loop. The area of a circle is calculated using:

A = πR²

For the larger loop with a radius of 20 cm (0.2 m):

A = π(0.2)² = π(0.04) ≈ 0.1256 m²

Now, substituting the values into the flux equation:

Φ = (3.37 x 10-5 T) * (0.1256 m²)

Calculating this gives:

Φ ≈ 4.23 x 10-6 Wb

Final Result

Thus, the magnetic flux linked with the larger loop due to the current in the smaller loop is approximately 4.23 x 10-6 Weber. This value illustrates how even a small current in a small loop can influence a much larger loop, showing the interconnectedness of magnetic fields in different sizes of circuits.

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