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A bullet of mass 7g is fired at a velocity of 900 ms-1 from a rifle of mass 3.5 kg. What is the recoil velocity of the rifle? A 0.9 ms-1 B 180 ms-1 C 900 ms-1 D 1.8 ms-1

aditya kashyap , 10 Years ago
Grade upto college level
anser 2 Answers
Saurabh Koranglekar

Last Activity: 4 Years ago

Dear student

Here I have used the law of conservation of momentum:
M1×U1+M2×U2=M1V1×M2V2

Regards

Arun

Last Activity: 4 Years ago

m1 = 5 g = 0.005 kg
m2 = 2.5 kg
v1 = 900 m/s
v2 = ?
 
# Solution-
Initially both gun and bullet are at rest.
 
Initial momentum is-
p1 = m1u1 + m2u2
p1 = 0.005×0 + 2.5×0
p1 = 0
 
Final momentum is-
p2 = m1v1 + m2v2
p2 = 0.005×900 + 2.5×v2
p2 = 4.5 + 2.5v2
 
By law of conservation of momentum-
p1 = p2
0 = 4.5 + 2.5v2
v2 = -4.5/2.5
v2 = -1.8 m/s
 
Therefore, recoil velocity of the gun is 1.8 m/s in opposite direction as that of bullet.
 
 

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