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A box B1 contains 1 white ball, 3 red balls and 2 black balls. Another box B2 contains 2 white balls, 3 red balls and 4 black balls. A third box B3 contains 3 white balls, 4 red balls and 5 black balls. Q.1 If 1 ball is drawn from each of the boxes B1, B2 and B3, the probability that all 3 drawn balls are of the same colour is (A) 82/ 648 (B) 90/ 648 (C) 558/ 648 (D) 566 /648

A box B1 contains 1 white ball, 3 red balls and 2 black balls. Another box B2 contains 2 white balls, 3 red balls and 4 black balls. A third box B3 contains 3 white balls, 4 red balls and 5 black balls.
Q.1 If 1 ball is drawn from each of the boxes B1, B2 and B3, the probability that all 3 drawn balls are of the same colour is
(A) 82/ 648
(B) 90/ 648
(C) 558/ 648
(D) 566 /648

Grade:11

2 Answers

Saurabh Koranglekar
askIITians Faculty 10341 Points
one year ago
576-1657_n.PNG
Vikas TU
14149 Points
one year ago

Let us denote B1, B2, B3 be the event of selecting 1st,2nd and 3rd box, respectively. Now suppose W be the event of white ball being taken out

So we are to find out P(B2 | W)

Use bayes theorem to get the ans

=[P(B2) P(W|B2)] /[P(B2) P(W|B2) +P(B1) P(W|B1) P(B3) P(W|B3)]

=(3/10)/(3/10+4/7+2/5)

=21/89

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