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Let us denote B1, B2, B3 be the event of selecting 1st,2nd and 3rd box, respectively. Now suppose W be the event of white ball being taken out
So we are to find out P(B2 | W)
Use bayes theorem to get the ans
=[P(B2) P(W|B2)] /[P(B2) P(W|B2) +P(B1) P(W|B1) P(B3) P(W|B3)]
=(3/10)/(3/10+4/7+2/5)
=21/89
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