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A body of mass 500 gram is rotating in a vertical circle of radius 1 m. What is the difference in its kinetic energies at the top and the bottom of the circle?(a) 4.9 J(b) 19.8 J(c) 2.8 J(d) 9.8 J

sumit kumar , 11 Years ago
Grade Upto college level
anser 2 Answers
Saurabh Koranglekar

Last Activity: 4 Years ago

Dear student

Please find the link attached

https://www.askiitians.com/forums/Mechanics/a-body-of-mass-500-gram-is-rotating-in-a-vertical_176078.htm

Regards

Vikas TU

Last Activity: 4 Years ago

Active vitality at Top = K.E. 
Active vitality at base = K.E. + mgD 
= K.E. + 2mgR 
Distinction = 2mgR 
= 2* 0.5 * 9.8 *1 
= 9.8 J

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