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Grade Upto college level Engineering Entrance Exams

A body of mass 500 gram is rotating in a vertical circle of radius 1 m. What is the difference in its kinetic energies at the top and the bottom of the circle? (a) 4.9 J (b) 19.8 J (c) 2.8 J (d) 9.8 J

Profile image of sumit kumar
12 Years agoGrade Upto college level
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2 Answers

Profile image of Vikas TU
6 Years ago
Active vitality at Top = K.E. 
Active vitality at base = K.E. + mgD 
= K.E. + 2mgR 
Distinction = 2mgR 
= 2* 0.5 * 9.8 *1 
= 9.8 J

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