×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
A body is dropped from the top of the tower falls 100m during last 2 sec of its falls. The time taken to reach the ground from the top of the tower

```
2 years ago

Eshan
2095 Points
```							Dear student,Let total time to reach the ground be.Hence distance travelled in time$\dpi{80} 't'$is$\dpi{80} s_t=\dfrac{1}{2}gt^2$Distance travelled in time ‘t-2’ is$\dpi{80} s_{t-2}=\dfrac{1}{2}g(t-2)^2$Therefore$\dpi{80} 100=\dfrac{1}{2}g(t^2-(t-2)^2)$$\dpi{80} \implies t=6s$
```
2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Engineering Entrance Exams

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions