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A binary liquid solution is prepared by mixing n-heptane and ethanol. Which one of the following statements is correct regarding the behaviour of the solution ? ?

sudhanshu , 11 Years ago
Grade 12
anser 2 Answers
Saurabh Koranglekar

Last Activity: 5 Years ago

n-Heptane is non-polar and ethanol is polar. Hence in the mixture formed by these two liquids is non-ideal. The stronger forces of attraction between n-heptane-n-heptane and ethanol-ethanol are replaced by weaker forces of attraction between n-heptane-ethanol in the solution. Therefore the escaping tendency of the liquid molecules into the vapour phase increases. This will increase the vapour pressure more than expected from Raoult's law. This is a positive deviation.
Vikas TU

Last Activity: 5 Years ago

(A) n-heptone: Non polar
(B) Ethanol: Polar
FA−B is less than FA−A'FB−B⇒+ deviation
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