Sanskar Goyal
Last Activity: 6 Years ago
Given, Volume of Oxalic Acid = 50ml = 0.05L
Initial Concentration- 1M
Final Concentration- 0.5M
So, Initial Moles- (0.05*1)= 0.05moles
Final Moles- (0.05*0.5)= 0.025moles
Change in Moles= 0.05-0.025 = 0.025moles
Now, Amount adsorbed=

So, (0.025*90.03)/0.5 = 4.5015 grams
Thanks,
Sanskar Goyal