Normal 0false false falseEN-US X-NONE X-NONE/* Style Definitions */table.MsoNormalTable{mso-style-name:Table Normal;mso-tstyle-rowband-size:0;mso-tstyle-colband-size:0;mso-style-noshow:yes;mso-style-priority:99;mso-style-parent:;mso-padding-alt:0in 5.4pt 0in 5.4pt;mso-para-margin-top:0in;mso-para-margin-right:0in;mso-para-margin-bottom:10.0pt;mso-para-margin-left:0in;line-height:115%;mso-pagination:widow-orphan;font-size:11.0pt;font-family:Calibri,sans-serif;mso-ascii-font-family:Calibri;mso-ascii-theme-font:minor-latin;mso-hansi-font-family:Calibri;mso-hansi-theme-font:minor-latin;mso-bidi-font-family:Times New Roman;mso-bidi-theme-font:minor-bidi;}The current gain for a transistor working as common-base amplifier is 0.96. If the emitter current is 7.2 mA, then the base current is(a) 0.29mA(b) 0.35mA(c) 0.39mA(d) 0.43mA
Amit Saxena , 11 Years ago
Grade upto college level
1 Answers
Aditi Chauhan
Last Activity: 11 Years ago
(a)
Current gain (a) =0.96
Ic = 0.96 × 7.2 mA = 6.91 mA
Ic = Ic + Ib
Ib = Ie – Ic = 7.2 - 6.91 = 0.29 mA
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