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One face of a rectangular glass plate 6 cm thick is silvered. An object held 8 cm in front of the first face forms an image 12 cm behind the silvered face. The refractive index of the glass is (a)0.4 (b) 0.8 (c)1.2 (d)1.6

One face of a rectangular glass plate 6 cm thick is silvered. An object held 8 cm in front of the first face forms an image 12 cm behind the silvered face. The refractive index of the glass is
(a)0.4
(b) 0.8
(c)1.2
(d)1.6

Grade:10

3 Answers

Navjyot Kalra
askIITians Faculty 654 Points
8 years ago

(c)

Thickness of glass plate (t) = 6 cm;

Distance of the object (u) = 8 cm.

And distance of the image (v) = 12 cm.

Let x = Apparent position of the silvered surface in cm,

Since the image is formed due to reflection at the silvered face and by the property of mirror image

Distance of object from the mirror = Distance of image from the mirror

or, x + 8 = 12 + 6 – x Þ x = 5 cm.

Therefore, refractive index of glass

Rishabh
11 Points
3 years ago
The distance of object form silvered surface= 8+6= 14cm The distance of image from silvered surface = 12 cmRefractive index = The distance of object form silvered surface/ The distance of image from silvered surfaceRefractive index = 14/12 = 1.1667 = 1.2
Kushagra Madhukar
askIITians Faculty 629 Points
one year ago
Dear student,
Please find the solution to your problem below.
 
Thickness of glass plate (t) = 6 cm;
Distance of the object (u) = 8 cm.
And distance of the image (v) = 12 cm.
Let x = Apparent position of the silvered surface in cm,
Since the image is formed due to reflection at the silvered face and by the property of mirror image
Distance of object from the mirror = Distance of image from the mirror
or, x + 8 = 12 + 6 – x 
Hence, x = 5 cm.
Therefore, refractive index of glass = real depth/apparent depth = 6/5 = 1.2
 
Hope it helps.
Thanks and regards,
Kushagra

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