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A stone released with zero velocity from the top of a tower, reaches the ground in 4 sec. The height of the tower is (g = 10m /s 2 ) (a) 20 m (b) 40 m (c) 80 m (d) 160 m



A stone released with zero velocity from the top of a tower, reaches the ground in 4 sec. The height of the tower is (g = 10m /s2)


        (a)    20 m        


(b)    40 m


        (c)    80 m        


(d)    160 m


Grade:10

1 Answers

Amit Saxena
35 Points
7 years ago

(c)
Initial velocity (u) = 0; Time (t) = 4 sec and gravitational acceleration (g) = 10 m/s2.
Height of tower
    h=  ut+  1/2   gt^2= (0×4 )+1/2×10× (4)^2   
    = 80 m.

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