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A particle of mass M is moving in a horizontal circle of radius R with uniform speed V. When it moves from one point to a diametrically opposite point, its
(a) Kinetic energy change by MV2/4
(b) Momentum does not change
(c) Momentum changes by 2 MV
(d) Kinetic energy changes by MV2
(c)
On the diametrically opposite points, the velocities have same magnitude but opposite directions. Therefore, change in momentum is MV-(- MV) = 2MV
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