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A particle of mass M is moving in a horizontal circle of radius R with uniform speed V. When it moves from one point to a diametrically opposite point, its (a) Kinetic energy change by MV 2 /4 (b) Momentum does not change (c) Momentum changes by 2 MV (d) Kinetic energy changes by MV 2



        A particle of mass M is moving in a horizontal circle of radius R with uniform speed V. When it moves from one point to a diametrically opposite point, its


(a)    Kinetic energy change by MV2/4


(b)    Momentum does not change


(c)    Momentum changes by 2 MV


(d)    Kinetic energy changes by MV2


Grade:11

1 Answers

Navjyot Kalra
askIITians Faculty 654 Points
9 years ago

(c)

On the diametrically opposite points, the velocities have same magnitude but opposite directions. Therefore, change in momentum is MV-(- MV) = 2MV

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