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N molecules each of mass m of a gas A and 2N molecules each of mass 2m of gas B are contained in the same vessel which is maintained at temperature T. The mean square velocity of molecules of B type is v2 and the mean square rectangular component of the velocity of A type is denoted by w2. Then w2/v2
(a) 2
(b) 1
(c) 1/3
(d) 2/3
(d)
Mean kinetic energy of the two types of molecules should be equal. The mean square velocity of A type molecules = w2 + w2 + w2 = 3w2.
Therefore,
This gives m2/v2 = 2/3
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