Normal 0false false falseEN-US X-NONE X-NONE/* Style Definitions */table.MsoNormalTable{mso-style-name:Table Normal;mso-tstyle-rowband-size:0;mso-tstyle-colband-size:0;mso-style-noshow:yes;mso-style-priority:99;mso-style-parent:;mso-padding-alt:0in 5.4pt 0in 5.4pt;mso-para-margin-top:0in;mso-para-margin-right:0in;mso-para-margin-bottom:10.0pt;mso-para-margin-left:0in;line-height:115%;mso-pagination:widow-orphan;font-size:11.0pt;font-family:Calibri,sans-serif;mso-ascii-font-family:Calibri;mso-ascii-theme-font:minor-latin;mso-hansi-font-family:Calibri;mso-hansi-theme-font:minor-latin;mso-bidi-font-family:Times New Roman;mso-bidi-theme-font:minor-bidi;}A stone projected at an angle q with horizontal from the roof of a tall building falls on the ground after three seconds. Two seconds after the projected it was again at the level of projection. Then the height of the building is(a) 15 m(b) 5 m(c) 25 m(d) 20 m
Amit Saxena , 11 Years ago
Grade upto college level
1 Answers
Simran Bhatia
Last Activity: 11 Years ago
(a)
TAC = 2 sec.
So, (2u sinx)/g = 2 => u sinx = g = 10 m/s
Now y = uyt + 1/2 ayt2 ==>– h = u sinx × 3 -1/2 g × 32
–h = 10 × 3 -1/2 × 10 × 9 => – h = 30 – 45
h = 45 – 30 = 15 m
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