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A particle is projected from a tower as shown in figure, then the distance from the foot of the tower where it will strike the ground will be – (take g = 10 m/s 2 and sin 37 o = 0.6) (a) 4000/3 m (b) 5000/3 m (c) 2000 m (d) 3000 m



A particle is projected from a tower as shown in figure, then the distance from the foot of the tower where it will strike the ground will be – (take g = 10 m/s2 and sin 37o =0.6)


 


(a)    4000/3 m


(b)    5000/3 m


(c)    2000 m


(d)    3000 m



 


Grade:upto college level

2 Answers

Simran Bhatia
348 Points
10 years ago

(a)

    –1500 = –100t – 1/2 × 10t2

     t^2/2 + 10t – 150 = 0 => t = (-20±40)/2

    So, t = 10 sec. i.e., horizontal distance

    = 500/3×4/3×10=4000/3 m

Bipasha Kalita
13 Points
5 years ago
y=Uy - 1/2 gt^2.    -1500=500/3×sin37°t-5t^2
                             Solving for t we get,
                                  t=10
   Range,D=Ux t. =500/3 × cos 37°×10
                             =4000/3m

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