The formula W = (F + 2Ma)v n , where W is the work done, F is the force, M is the mass, a is the acceleration and v is the velocity, can be made dimensionally correct for (a) n = 0 (b) n = 1 (c) n = –1 (d) no value of n

Question

The formula W = (F + 2Ma)v n , where W is the work done, F is the force, M is the mass, a is the acceleration and v is the velocity, can be made dimensionally correct for (a) n = 0 (b) n = 1 (c) n = &ndash;1 (d) no value of n

Simran Bhatia · Answer

(d)

Since work done is always equal to the product of force and distance and in no ways velocity can be substitute for distance/displacement. So the relation holds good for “no value of n”.

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The formula W = (F + 2Ma)v n , where W is the work done, F is the force, M is the mass, a is the acceleration and v is the velocity, can be made dimensionally correct for (a) n = 0 (b) n = 1 (c) n = –1 (d) no value of n

The formula W = (F + 2Ma)vⁿ, where W is the work done, F is the force, M is the mass, a is the acceleration and v is the velocity, can be made dimensionally correct for

        (a)    n = 0

        (b)    n = 1

        (c)    n = –1

        (d)    no value of n

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The formula W = (F + 2Ma)v n , where W is the work done, F is the force, M is the mass, a is the acceleration and v is the velocity, can be made dimensionally correct for (a) n = 0 (b) n = 1 (c) n = –1 (d) no value of n

The formula W = (F + 2Ma)vn, where W is the work done, F is the force, M is the mass, a is the acceleration and v is the velocity, can be made dimensionally correct for (a) n = 0 (b) n = 1 (c) n = –1 (d) no value of n

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The formula W = (F + 2Ma)vⁿ, where W is the work done, F is the force, M is the mass, a is the acceleration and v is the velocity, can be made dimensionally correct for

(a) n = 0

(b) n = 1

(c) n = –1

(d) no value of n