A 5.82 g silver coin is dissolved in nitric acid. When sodium chloride is added to the solution, all the silver is precipitated as AgCl. The AgCl precipitate weights 7.20 g. What is the percentage of solver in coin?(A) 98%(B) 93.1%(C) 86%(D) 82%
Simran Bhatia , 11 Years ago
Grade 11
1 Answers
Shane Macguire
Last Activity: 11 Years ago
Fraction of Ag in AgCl = weight of Ag in 7.20 g AgCl
= 0.753 × 7.20 g = 5.42 g Ag
Hence the 5.82 g coin contains 5.42 g Ag = 0
Fraction of Ag in coin = 5.42 g/5.82 g
= 0.931 = 93.1 % Ag
Provide a better Answer & Earn Cool Goodies
Enter text here...
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Ask a Doubt
Get your questions answered by the expert for free
Enter text here...
Other Related Questions on Engineering Entrance Exams