The threshold frequency of a metal is 4 × 1014 s–1. The minimum energy which photons must possess to produce photoelectric effect with the metal is (h = 6.6 × 10–34 Js)(A) 3.06 × 10–12 J(B) 1.4 × 10–48 J(C) 3.4 × 10–19 J(D) 6.023 × 10–19 J
Radhika Batra , 11 Years ago
Grade 11
1 Answers
Amit Saxena
Last Activity: 11 Years ago
Threshold energy required for emission
= hv0 = 6.6 × 10–34 × 4 × 1014
= 2.64 × 10–19 J
Provide a better Answer & Earn Cool Goodies
Enter text here...
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Ask a Doubt
Get your questions answered by the expert for free
Enter text here...
Other Related Questions on Engineering Entrance Exams