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The pKa of an acid having ionization constant 1 × 10−5 is (A) 5 (B) −5 (C) −9 (D) 9

The pKa of an acid having ionization constant 1 × 10−5 is
    (A)    5
    (B)    −5
    (C)    −9
    (D)    9

Grade:upto college level

1 Answers

Radhika Batra
247 Points
10 years ago

pKa = − log Ka (Ka = dissociation constant or ionization constant).

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