The coagulation of 100 mL of colloidal solution of gold is completely prevented by addition of 0.25 g of a substance ‘X’ to it, before adding 1 ml of 10% NaCl solution. The gold number of X is
    (A)    0.25
    (B)    25
    (C)    250
    (D)    2.5

Question

Radhika Batra · Answer

Amt. of protective colloid added in milligrams = 0.25 &times; 1000 = 250 Hence By definition, the protective colloid required for 10 ml. =250/100&times;10=25

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The coagulation of 100 mL of colloidal solution of gold is completely prevented by addition of 0.25 g of a substance ‘X’ to it, before adding 1 ml of 10% NaCl solution. The gold number of X is (A) 0.25 (B) 25 (C) 250 (D) 2.5

The coagulation of 100 mL of colloidal solution of gold is completely prevented by addition of 0.25 g of a substance ‘X’ to it, before adding 1 ml of 10% NaCl solution. The gold number of X is
    (A)    0.25
    (B)    25
    (C)    250
    (D)    2.5

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The coagulation of 100 mL of colloidal solution of gold is completely prevented by addition of 0.25 g of a substance ‘X’ to it, before adding 1 ml of 10% NaCl solution. The gold number of X is (A) 0.25 (B) 25 (C) 250 (D) 2.5

The coagulation of 100 mL of colloidal solution of gold is completely prevented by addition of 0.25 g of a substance ‘X’ to it, before adding 1 ml of 10% NaCl solution. The gold number of X is (A) 0.25 (B) 25 (C) 250 (D) 2.5

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The coagulation of 100 mL of colloidal solution of gold is completely prevented by addition of 0.25 g of a substance ‘X’ to it, before adding 1 ml of 10% NaCl solution. The gold number of X is
(A) 0.25
(B) 25
(C) 250
(D) 2.5