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Grade upto college level Engineering Entrance Exams

The coagulation of 100 mL of colloidal solution of gold is completely prevented by addition of 0.25 g of a substance ‘X’ to it, before adding 1 ml of 10% NaCl solution. The gold number of X is
(A) 0.25
(B) 25
(C) 250
(D) 2.5

Profile image of Amit Saxena
12 Years agoGrade upto college level
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1 Answer

Profile image of Radhika Batra
12 Years ago

Amt. of protective colloid added in milligrams = 0.25 × 1000 = 250

    Hence By definition, the protective colloid required for 10 ml. =250/100×10=25


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