Flag Engineering Entrance Exams> coagulation...
question mark

The coagulation of 100 mL of colloidal solution of gold is completely prevented by addition of 0.25 g of a substance ‘X’ to it, before adding 1 ml of 10% NaCl solution. The gold number of X is
(A) 0.25
(B) 25
(C) 250
(D) 2.5

Amit Saxena , 12 Years ago
Grade upto college level
anser 1 Answers
Radhika Batra

Amt. of protective colloid added in milligrams = 0.25 × 1000 = 250

    Hence By definition, the protective colloid required for 10 ml. =250/100×10=25

Last Activity: 12 Years ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments



question mark
Hello,
 
Can we learn and prepare for MHT-CET online ?
engineering entrance exams
1 Answer Available

Last Activity: 4 Years ago