Kushagra Madhukar
Last Activity: 4 Years ago
Dear student,
Please find the solution to your problem below.
We know, max acceleration during SHM = amax = w2A = (2π/T)2 x A
Hence,T = 2π√(A/amax)
Now, amax = g = 9.81
Hence, T = 2π√(3.92 x 10-3/9.81)
Hence, T = 0.12553 s
Hence correct answer is (d) 0.1256 s
Hope it helps.
Thanks and regards,
Kushagra