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Grade 11Engineering Entrance Exams

A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is 3.92 × 10–3 m. What must be the least period of these oscillations, so that the object is not detached from the platform?
(A) 0.1356 sec
(B) 0.1456 sec
(C) 0.1556 sec
(D) 0.1256 sec

Profile image of Radhika Batra
12 Years agoGrade 11
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3 Answers

Profile image of Shane Macguire
12 Years ago

Profile image of mukunda
12 Years ago

hii   ans is D(0.1256).     bye.         

Profile image of Kushagra Madhukar
5 Years ago
Dear student,
Please find the solution to your problem below.
 
We know, max acceleration during SHM = amax = w2A = (2π/T)2 x A
Hence,T = 2π√(A/amax)
Now, amax = g = 9.81
Hence, T = √(3.92 x 10-3/9.81)
Hence, T = 0.12553 s
Hence correct answer is (d) 0.1256 s
 
Hope it helps.
Thanks and regards,
Kushagra

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Hello,
 
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