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The electric field due to a positive charge at a distance 1 m is 4 NC–1. Its magnitude at distance 2 m will be (A) 0.5 NC–1 (B) 1 NC–1 (C) 2 NC–1 (D) none of the above

The electric field due to a positive charge at a distance 1 m is 4 NC–1. Its magnitude at distance 2 m will be
    (A)    0.5 NC–1
    (B)    1 NC–1
    (C)    2 NC–1
    (D)    none of the above

Grade:upto college level

3 Answers

Radhika Batra
247 Points
8 years ago

Arbaz IIIT
31 Points
8 years ago

E1=4 N/C,

r1=1,

therefore,E1=(k x q )/r1^2

q=E1/k ----------(1)

Given r2=2

E2=(k x q)/r2^2 [By substituting (1)]

E2=E1/4

E2=1

 

Ans:(B)

vamsi
43 Points
8 years ago

E=4/4=1N/C

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