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The electric field due to a positive charge at a distance 1 m is 4 NC–1. Its magnitude at distance 2 m will be (A) 0.5 NC–1 (B) 1 NC–1 (C) 2 NC–1 (D) none of the above
E1=4 N/C,
r1=1,
therefore,E1=(k x q )/r1^2
q=E1/k ----------(1)
Given r2=2
E2=(k x q)/r2^2 [By substituting (1)]
E2=E1/4
E2=1
Ans:(B)
E=4/4=1N/C
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