A shell initially at rest explodes into two pieces of equal mass. Then the two pieces will be

(A)    at rest

(B)    move with same velocity in opposite directions

(C)    move with same velocity in same direction

(D)    move with different velocities in different directions

Question

A shell initially at rest explodes into two pieces of equal mass. Then the two pieces will be

(A) at rest

(B) move with same velocity in opposite directions

(C) move with same velocity in same direction

(D) move with different velocities in different directions

Amit Saxena · Answer

Khandavalli Satya Srikanth · Answer

By momentum conservation theorem momentum before explosion is equal to momentum after explosion. Momentum before explosion is zero(because they are rest).Then momentum after explosion is zero. There fore two pieces are at rest.

Rishi Sharma · Answer

Dear Student,
Please find below the solution to your problem.

By momentum conservation theorem momentum before explosion is equal to momentum after explosion.
Momentum before explosion is zero(because they are rest.
Then momentum after explosion is zero.
There fore two pieces are at rest

Thanks and Regards

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A shell initially at rest explodes into two pieces of equal mass. Then the two pieces will be (A) at rest (B) move with same velocity in opposite directions (C) move with same velocity in same direction (D) move with different velocities in different directions

A shell initially at rest explodes into two pieces of equal mass. Then the two pieces will be

(A)    at rest

(B)    move with same velocity in opposite directions

(C)    move with same velocity in same direction

(D)    move with different velocities in different directions

3 Answers

By momentum conservation theorem momentum before explosion is equal to momentum after explosion.

Momentum before explosion is zero(because they are rest).Then momentum after explosion is zero. There fore two pieces are at rest.

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