50 ml of 1 M oxalic acid is shaked with 0.5 g wood charcoal. The final concentration of the solution after adsorption is 0.5 M. What is the amount of oxalic acid absorbed per gram of carbon?

        (A)    3.15 g

        (B)    3.45 g

        (C)    6.30 g

(D)    None

Question

50 ml of 1 M oxalic acid is shaked with 0.5 g wood charcoal. The final concentration of the solution after adsorption is 0.5 M. What is the amount of oxalic acid absorbed per gram of carbon?

(A) 3.15 g

(B) 3.45 g

(C) 6.30 g

(D) None

Amit Saxena · Answer

India VK · Answer

D Amount of acid in the soln to begin with = 50 * 1 = 50 mmol At the end = 0.5 * 50 = 25 mmol Adsorbed = 25 mmol = 25*90/1000 = 2.25 g Adsorbed / gm or charcoal = 2.25/.5 = 4.5

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50 ml of 1 M oxalic acid is shaked with 0.5 g wood charcoal. The final concentration of the solution after adsorption is 0.5 M. What is the amount of oxalic acid absorbed per gram of carbon? (A) 3.15 g (B) 3.45 g (C) 6.30 g (D) None

50 ml of 1 M oxalic acid is shaked with 0.5 g wood charcoal. The final concentration of the solution after adsorption is 0.5 M. What is the amount of oxalic acid absorbed per gram of carbon?

        (A)    3.15 g

        (B)    3.45 g

        (C)    6.30 g

(D)    None

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50 ml of 1 M oxalic acid is shaked with 0.5 g wood charcoal. The final concentration of the solution after adsorption is 0.5 M. What is the amount of oxalic acid absorbed per gram of carbon? (A) 3.15 g (B) 3.45 g (C) 6.30 g (D) None

50 ml of 1 M oxalic acid is shaked with 0.5 g wood charcoal. The final concentration of the solution after adsorption is 0.5 M. What is the amount of oxalic acid absorbed per gram of carbon? (A) 3.15 g (B) 3.45 g (C) 6.30 g (D) None

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50 ml of 1 M oxalic acid is shaked with 0.5 g wood charcoal. The final concentration of the solution after adsorption is 0.5 M. What is the amount of oxalic acid absorbed per gram of carbon?

(A) 3.15 g

(B) 3.45 g

(C) 6.30 g

(D) None