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If te solubility of MX2 (a sparingly soluble salt is 2.5 × 10–14 mol l−1. The value of Ksp of the salt would be)

(A) 6.25 × 10−11

(B) 12.5 × 11−8

(C) 6.25 × 10−8

(D) 3.125 × 10−11

Amit Saxena , 12 Years ago
Grade upto college level
anser 1 Answers
Shane Macguire

Last Activity: 12 Years ago

Ksp = 4s2 \ 4 × (2.5 × 10−4)3 = 6.25 × 10−11

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