If te solubility of MX2 (a sparingly soluble salt is 2.5 × 10–14 mol l−1.The value of Ksp of the salt would be)(A) 6.25 × 10−11(B) 12.5 × 11−8(C) 6.25 × 10−8(D) 3.125 × 10−11
Amit Saxena , 11 Years ago
Grade upto college level
1 Answers
Shane Macguire
Last Activity: 11 Years ago
Ksp = 4s2 \ 4 × (2.5 × 10−4)3 = 6.25 × 10−11
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