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If te solubility of MX 2 (a sparingly soluble salt is 2.5 × 10 –14 mol l −1 . The value of K sp of the salt would be) (A) 6.25 × 10 −11 (B) 12.5 × 11 −8 (C) 6.25 × 10 −8 (D) 3.125 × 10 −11

If te solubility of MX2 (a sparingly soluble salt is 2.5 × 10–14 mol l−1.     The value of Ksp of the salt would be)


        (A)    6.25 × 10−11


        (B)    12.5 × 11−8


        (C)    6.25 × 10−8


 


        (D)    3.125 × 10−11

Grade:upto college level

1 Answers

Shane Macguire
30 Points
7 years ago

Ksp = 4s2 \ 4 × (2.5 × 10−4)3 = 6.25 × 10−11

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