A 5.82 g silver coin is dissolved in nitric acid. When sodium chloride is added to the solution, all the silver is precipitated as AgCl. The AgCl precipitate weights 7.20 g. What is the percentage of solver in coin?(A) 98%(B) 93.1%(C) 86%(D) 82%
Amit Saxena , 11 Years ago
Grade upto college level
1 Answers
Shane Macguire
Last Activity: 11 Years ago
Fraction of Ag in AgCl = 107.9/143.3= 0.753 weight of Ag in 7.20 g AgCl
= 0.753 × 7.20 g = 5.42 g Ag
Hence the 5.82 g coin contains 5.42 g Ag = 0
Fraction of Ag in coin = 5.42 g/5.82 g
= 0.931 = 93.1 % Ag
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