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4. The threshold frequency of a metal is 4 × 1014 s–1. The minimum energy which photons must possess to produce photoelectric effect with the metal is (h = 6.6 × 10–34 Js)

(A) 3.06 × 10–12 J

(B) 1.4 × 10–48 J

(C) 3.4 × 10–19 J

(D) 6.023 × 10–19 J

Radhika Batra , 12 Years ago
Grade 11
anser 1 Answers
Deepak Patra

Threshold energy required for emission

 

= hv0 = 6.6 × 10–34 × 4 × 1014

 

= 2.64 × 10–19

Last Activity: 12 Years ago
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