2.     One among the following set of quantum numbers defines the highest energy electron in scandium (I) ion

(A)        n = 3, l = 1, m = 0, s = –1/2

(B)        n = 3, l = 0, m = 0, s = –1/2

(C)        n = 4, l = 0, m = 0, s = +1/2

(D)        n = 3, l = 2, m = 2, s = +1/2.

Question

2. One among the following set of quantum numbers defines the highest energy electron in scandium (I) ion

(A) n = 3, l = 1, m = 0, s = –1/2

(B) n = 3, l = 0, m = 0, s = –1/2

(C) n = 4, l = 0, m = 0, s = +1/2

(D) n = 3, l = 2, m = 2, s = +1/2.

Deepak Patra · Answer

21 Se + ion has conf. = 1s 2 2s 2 2p 6 3s 2 3d 1 4s 1 . Highest energy electron is 4s. During ionization such electron is removed fist from 4s orbital only. Although 3d is filled after 4s.

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2. One among the following set of quantum numbers defines the highest energy electron in scandium (I) ion (A) n = 3, l = 1, m = 0, s = –1/2 (B) n = 3, l = 0, m = 0, s = –1/2 (C) n = 4, l = 0, m = 0, s = +1/2 (D) n = 3, l = 2, m = 2, s = +1/2.

2.     One among the following set of quantum numbers defines the highest energy electron in scandium (I) ion

(A)        n = 3, l = 1, m = 0, s = –1/2

(B)        n = 3, l = 0, m = 0, s = –1/2

(C)        n = 4, l = 0, m = 0, s = +1/2

(D)        n = 3, l = 2, m = 2, s = +1/2.

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