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2. One among the following set of quantum numbers defines the highest energy electron in scandium (I) ion (A) n = 3, l = 1, m = 0, s = –1/2 (B) n = 3, l = 0, m = 0, s = –1/2 (C) n = 4, l = 0, m = 0, s = +1/2 (D) n = 3, l = 2, m = 2, s = +1/2.

2.     One among the following set of quantum numbers defines the highest energy electron in scandium (I) ion


(A)        n = 3, l = 1, m = 0, s = –1/2


(B)        n = 3, l = 0, m = 0, s = –1/2


(C)        n = 4, l = 0, m = 0, s = +1/2


 


(D)        n = 3, l = 2, m = 2, s = +1/2.

Grade:upto college level

1 Answers

Deepak Patra
askIITians Faculty 471 Points
9 years ago

21Se+ ion has conf. = 1s2 2s2 2p6 3s2 3d1 4s1.

 

Highest energy electron is 4s.

 

During ionization such electron is removed fist from 4s orbital only. Although 3d is filled after 4s. 

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