If the dimensions of the length are expressed as Gxcyhz; where G, c and h are the universal gravitational constant, speed of light and Planck’s constant respectively, then

(a)     X = ½, y = ½

(b)     x = 1/2 , z = 1/2

(c)     y = ½, z = 3/2

(d)     y = –3/2, z = ½

Question

If the dimensions of the length are expressed as Gxcyhz; where G, c and h are the universal gravitational constant, speed of light and Planck’s constant respectively, then

(a) X = ½, y = ½

(b) x = 1/2 , z = 1/2

(c) y = ½, z = 3/2

(d) y = –3/2, z = ½

Avinash · Answer

L = [M -1 L 3 T -2 ] x [LT -1 ] y [ML 2 T -1 ] z should has zero as power of M, so x = z. Sox = 1/2 , z = 1/2

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If the dimensions of the length are expressed as Gxcyhz; where G, c and h are the universal gravitational constant, speed of light and Planck’s constant respectively, then (a) X = ½, y = ½ (b) x = 1/2 , z = 1/2 (c) y = ½, z = 3/2 (d) y = –3/2, z = ½

If the dimensions of the length are expressed as Gxcyhz; where G, c and h are the universal gravitational constant, speed of light and Planck’s constant respectively, then

(a)     X = ½, y = ½

(b)     x = 1/2 , z = 1/2

(c)     y = ½, z = 3/2

(d)     y = –3/2, z = ½

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If the dimensions of the length are expressed as Gxcyhz; where G, c and h are the universal gravitational constant, speed of light and Planck’s constant respectively, then (a) X = ½, y = ½ (b) x = 1/2 , z = 1/2 (c) y = ½, z = 3/2 (d) y = –3/2, z = ½

If the dimensions of the length are expressed as Gxcyhz; where G, c and h are the universal gravitational constant, speed of light and Planck’s constant respectively, then (a) X = ½, y = ½ (b) x = 1/2 , z = 1/2 (c) y = ½, z = 3/2 (d) y = –3/2, z = ½

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If the dimensions of the length are expressed as Gxcyhz; where G, c and h are the universal gravitational constant, speed of light and Planck’s constant respectively, then

(a) X = ½, y = ½

(b) x = 1/2 , z = 1/2

(c) y = ½, z = 3/2

(d) y = –3/2, z = ½