Question icon
Grade 10Engineering Entrance Exams

A stone is dropped into water from a bridge 44.1 m above the water. Another stone is thrown vertically downward 1 sec later. Both strike speed water simultaneously. What was the initial speed of the second stone?

(a) 12.25/s

(b) 14.75m/s

(c) 16.23m/s

(d) 17.15m/s

Profile image of Hrishant Goswami
12 Years agoGrade 10
Answers icon

2 Answers

Profile image of Keerthi Raj
12 Years ago

placing origin of the coordinate system at the point of dropping.

-44.1=-4.9t2 ==> t=3s

-44.1=2u-19.6 ==> u=-12.25m/s

Profile image of Yash Deshpande
8 Years ago
x=44.1m
a=9.8m/s2
u=0
Wkt,
x=ut+1/2gt2
44.1=1/2*9.8*t2
t2=441/49
t=3 sec. So the second stone will come down in 3-1=2sec
Therefore, applying the same eqn again we get,
44.1=2u+1/2*9.8*4
44.1=2u+19.6
u=12.25m/s

question mark
Hello,
 
Can we learn and prepare for MHT-CET online ?
engineering entrance exams

Last Activity: 4 Years ago