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Grade 10Engineering Entrance Exams

when t = 0, a particle at (1,0,0) moves towards (4,4,12) with a constant velocity of magnitude of 65 m/s. the position of the particle is measured in meters and time in sec. Assuming constant velocity the position of the particle at t= 2 sec is

(a) (13 – 120 +40) m

(b) (40 +31– 120) m

(c) (13 – 40 + 12) m

(d) (31 + 40+ 120) m

Profile image of Hrishant Goswami
12 Years agoGrade 10
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2 Answers

Profile image of Saurabh Koranglekar
6 Years ago
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Profile image of Vikas TU
6 Years ago
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Dear student 
Please refer the clear image , 
The image above does not looks good , it is blurr.
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