when t = 0, a particle at (1,0,0) moves towards (4,4,12) with a constant velocity of magnitude of 65 m/s. the position of the particle is measured in meters and time in sec. Assuming constant velocity the position of the particle at t= 2 sec is(a) (13– 120 +40) m(b) (40 +31– 120) m(c) (13 – 40+ 12) m(d) (31 + 40+ 120) m
Hrishant Goswami , 11 Years ago
Grade 10
2 Answers
Saurabh Koranglekar
Last Activity: 4 Years ago
Vikas TU
Last Activity: 4 Years ago
Dear student Please refer the clear image , The image above does not looks good , it is blurr. Hope for the best Good Luck Cheers
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