#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.

Click to Chat

1800-1023-196

+91 7353221155

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# find the equation tot he straight line passing through the point (3,2)and the point of intersection of the lines 2x+3y=1 and 3x-4y=6

## 1 Answers

7 years ago

First, find the common point between the two intersecting lines,

2x+3y=1  and  3x-4y=6 .

Solve them as a set of equations and you will get  x = 22/7 and y = -9/17

Then find the slope using, m = (y2-y1) / (x2-x1)

You''ll find, m = 43 / 29

Use y - y0 = m (x - x0) to get the equation.

It will look like: y - 2 = (43 / 29) (x - 3)

The final equation will be: 43x - 29y - 71 = 0

## ASK QUESTION

Get your questions answered by the expert for free