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find the equation tot he straight line passing through the point (3,2)and the point of intersection of the lines 2x+3y=1 and 3x-4y=6
First, find the common point between the two intersecting lines,
2x+3y=1 and 3x-4y=6 .
Solve them as a set of equations and you will get x = 22/7 and y = -9/17
Then find the slope using, m = (y2-y1) / (x2-x1)
You''ll find, m = 43 / 29
Use y - y0 = m (x - x0) to get the equation.
It will look like: y - 2 = (43 / 29) (x - 3)
The final equation will be: 43x - 29y - 71 = 0
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