A charge Q is placed at the centre of an imaginary hemispherical surface. Using symmetry arguments and the Gauss’s law.

The flux of electric field due to this charge through the surface of the hemisphere (figure) is.

Question

A charge Q is placed at the centre of an imaginary hemispherical surface. Using symmetry arguments and the Gauss’s law.

The flux of electric field due to this charge through the surface of the hemisphere (figure) is.

Aman Bansal · Answer

Dear Varna,

Flux=Q/2

Consider a spherical surface with the charge placed at its centre.
the flux thr it=q(enclosed)/
by symmetry the flux thr the hemispherical surface is half of the spherical one

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A charge Q is placed at the centre of an imaginary hemispherical surface. Using symmetry arguments and the Gauss’s law. The flux of electric field due to this charge through the surface of the hemisphere (figure) is.

A charge Q is placed at the centre of an imaginary hemispherical surface. Using symmetry arguments and the Gauss’s law.

The flux of electric field due to this charge through the surface of the hemisphere (figure) is.

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A charge Q is placed at the centre of an imaginary hemispherical surface. Using symmetry arguments and the Gauss’s law. The flux of electric field due to this charge through the surface of the hemisphere (figure) is.

A charge Q is placed at the centre of an imaginary hemispherical surface. Using symmetry arguments and the Gauss’s law. The flux of electric field due to this charge through the surface of the hemisphere (figure) is.

1 Answers

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A charge Q is placed at the centre of an imaginary hemispherical surface. Using symmetry arguments and the Gauss’s law.

The flux of electric field due to this charge through the surface of the hemisphere (figure) is.