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The electric potential V as a function of distance x (in meter ) is given by: V = ( 15x 2 +10x-9) V. The value of electric field of x=1m would be-

The electric potential V as a function of distance x (in meter) is given by: V = (15x2+10x-9) V. The value of electric field of x=1m would be-


4 Answers

Aman Bansal
592 Points
8 years ago

Dear Varna,

Since field is given as E = \begin{displaymath} E_x = - \frac{dV}{dx}. \end{displaymath}


Thus applying this forlumla na dthe substituting x = 1 , we get the field value.

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Aman Bansal

Askiitian Expert

chennabasava s patil
18 Points
8 years ago


Varna Sambhangi
33 Points
8 years ago

i think its 40...hw did you get it as 16??plzz xplain..

Yogita Bang
39 Points
8 years ago

E = dV/dx = d(15x2 + 10x - 9)/dx = 30x + 10 - 0

Put x=1,

E = 30 + 10 = 40   Smile

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