3 digit number divisible by 3 and two digits repeated.....???

3 digit number divisible by 3 and two digits repeated.....???


2 Answers

Aman Bansal
592 Points
10 years ago


For the number to be divisible by 4, the number formed by the last two digits must be divisible by 4. With the digits 1 through 6, you can use the 3 last digits 24 and 6, and each of these can be combined with half of the digits to form a 2-digit number divisible by 4, so there are 9combinations for the last two digits. The other two digits can be chosen arbitrarily, so there are 36combinations for those, for a total of 9\cdot 36=324 different numbers

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Aman Bansal

Askiitian Expert

Peetala Kishore
33 Points
10 years ago


suppose 114

to test this = 1+1+4 =6 .

six is divisable by 3 so

the given number also divisable by 3.

there are 66 possiblities are there for your question.

they are = {114,117,225,228,330,336,339,441,448,552,558,660,669,771,774,882,885,990,993,996} there is also possibloe of repetitions  other are 300,600,900.

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