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Q::force of attraction between two charged conductors A and B is F ,a third uncharged conductor is placed first near A and then near B THEN new force of attraction
Dear Archana,
Just follow law of conservation of charges, & distribute charges equally in both conductors, when they r close!!!!!!!! U will get ur ans.
Good Luck!!!!!!!!
Plz. approve by clicking 'Yes' given below!!!!!!!!!! Plz. Plz. Plz.!!!!!!!!!!!!!
Let the charges on A and B be q.
Now c is bought near to A, hence the charges would get evenly distributed, hence both, A and C will get charge q/2.
Now C is bought near B, hence both will get even charges. So, since A has q and C has q/2.. So, now they will get re-distributed and A will get 3q/4 and C will also get 3q/4.
Now new force of attraction be F'
Then,
F'=kq(3q)/2x4xr2 ..... (1)
But we know
F=kqq/r2 .....(2)
Hence, from (1) and (2)
F'=3F/8
Please Approve by clicking "Yes" below!!
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